4.9t^2-425t=0

Solution for 4.9t^2-425t=0 equation:

4.9t^2-425t=0

a = 4.9; b = -425; c = 0;
Δ = b2-4ac
Δ = -4252-4·4.9·0
Δ = 180625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{180625}=425$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-425)-425}{2*4.9}=\frac{0}{9.8}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-425)+425}{2*4.9}=\frac{850}{9.8}
=86+6/8.16666666667
$